Can you equate penile traction weight to PSI in pumps?

[tbean750]

I know I posted earlier on pumps but this set of questions is slightly different. Also a question on my $25 Amazon penis stretcher; can anyone tell in these pictures how many lbs or approximately how many pounds of tension this thing goes to at the max?
Pump questions: if PSI is pounds per square inch, can't you do the math to equate exactly to a penis stretcher but also get huge ass girth gains? Say find the equivelant to 6lbs of tension hold it but get that length gain plus the girth gain?

 

[oldandlively]

I know I posted earlier on pumps but this set of questions is slightly different. Also a question on my $25 Amazon penis stretcher; can anyone tell in these pictures how many lbs or approximately how many pounds of tension this thing goes to at the max?

If, and only if, it follows the standard scheme, the max spring tension is around 2.5lbs if it fully compresses. However, you can always test it using a kitchen scale. It's the easiest to measure the amount of compression each mark on the extender provides.

Pump questions: if PSI is pounds per square inch, can't you do the math to equate exactly to a penis stretcher but also get huge ass girth gains?

You can convert PSI to mmHg and inHg. Not sure what you're trying to calculate to obtain a "huge ass girth gains" in comparing negative pressure pull along the cylinder vs the constant traction force on the extender.

Here's an example. If you're using a pump, you're placing your penis under pressure at -10inHg, or around 4.9 psi. If you're trying to keep the pressure up for 15 minutes, your penis starts to build tons of edema. You try that for the next 4 hours, your penis will look like a balloon, that is, if your penis doesn't break by then.

Under a penis traction device like the extender, you can increase the initial traction force around 5lbs, then release back to 2.3lbs for the remaining hours, with a minimum of 4 hours under traction tension.

Say find the equivelant to 6lbs of tension hold it but get that length gain plus the girth gain?

Under 6lbs of tension, you'll place the penis under length influence for length gains. However, if you wear the extender or traction device at 6lbs past 60 minutes, I can tell you that your blood vessels and nerves will be destroyed after 24 hours, or they reach the point where your penis will not work for the next few months.

Under PE, we have to ensure total discipline of continuous routines, where safety is the highest priority. In this brotherhood, we focus on a mantra of, "PE is a marathon and not a race." If you believe PE should be fast and furious, your penis gains will be just as fast and furious, with an 70% or greater chance of broken.

 

[tbean750]

My theory is so say your penis pump tube it's 9in by two inches so the whole tube I believe would be 9x2x2 so 36in right now just estimate your penis is taking up halfish of the entire tube your doing 7psi so that would mean what's 36 square inches I googled it is 0.25 square feet that would be exactly 3 square inches so now 7x3 you got 21lbs of pressure I your 9inx2x2 penis pump but your penis is only taking up say half because of sides etc just say example penis so this should mea your penis is under exactly 10.5lbs of tension right now being stretched by the air and or water because that's 21 divided by 2

 

[oldandlively]

My theory is so say your penis pump tube it's 9in by two inches so the whole tube I believe would be 9x2x2 so 36in right now just estimate your penis is taking up halfish of the entire tube your doing 7psi so that would mean what's 36 square inches I googled it is 0.25 square feet that would be exactly 3 square inches so now 7x3 you got 21lbs of pressure I your 9inx2x2 penis pump but your penis is only taking up say half because of sides etc just say example penis so this should mea your penis is under exactly 10.5lbs of tension right now being stretched by the air and or water because that's 21 divided by 2

Let's take your method of approach, but make a correction on the mathematical equation:

Uniform cylinder: 9in length x 2in diameter x 2in travel/pulling length = not 36 in^2 of volume space. This is a wrong assumption.

• What you are looking at is how much space remaining in the cylinder occupied by the expanded penis. Let's say your penis managed to be packed inside the 9in x 2in uniform cylinder, and you have 2in of travel/pulling length, you're calculating for the traction force inside a negative pressure chamber.
• The influence of the entire exerted pressures on an empty cylinder on a surface area is 9in x 2in x 3.14in surface area of a 2in diameter cylinder = 56.52 in^3, or 0.033 ft^3.
• You're not exerting the same force because of the occupied body that is already occupied inside the cylinder, in additional to the subtraction of the surface area occupied around the base of the penis.

What you've attempted to do is using a flawed Boyle's Law approach in a vacuumed system for gas or liquid exerting on a surface area, something akin to a pulling force on a sealed flat surface. Unfortunately, you're not. You're pulling an occupied space. Pressure influences are completely different. Take into account of not only occupied space, but also expansion of the penis which reduces the total volume space of the cylinder. Remember the penis is a dynamic balloon and not a static surface area like a table. Higher PSI on a smaller volume and reduced surface area can increase the overall traction force by 2 to 5 times.

• Safety concerns: -7 psi = -14.2 inHg. Unless you are conditioned to go this high, this is where most penis will be injured. At 2 times of reduce surface volume and area, you have up to -28.4inHg. This is a higher risk for penile damage under static time period of 30 seconds or more.

If we're not seeing what you're seeing, do correct us. We have quite a few engineers and scientists in the forum.

 

[tbean750]

Nice!!!! TYVM for that math!!! And pointing out the difference in psi vs pulling definitely will stick with stretchers for length